Base | Representation |
---|---|
bin | 11000100010000001… |
… | …10011011111101001 |
3 | 1020222212021212002122 |
4 | 30101000303133221 |
5 | 203433100403411 |
6 | 10014513441025 |
7 | 644241630245 |
oct | 142100633751 |
9 | 36885255078 |
10 | 13170325481 |
11 | 564933a515 |
12 | 2676870175 |
13 | 131b769201 |
14 | 8cd225425 |
15 | 5213989db |
hex | 3110337e9 |
13170325481 has 8 divisors (see below), whose sum is σ = 13787721024. Its totient is φ = 12556661040.
The previous prime is 13170325451. The next prime is 13170325507. The reversal of 13170325481 is 18452307131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13170325481 - 210 = 13170324457 is a prime.
It is a super-2 number, since 2×131703254812 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13170325451) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 925550 + ... + 939671.
It is an arithmetic number, because the mean of its divisors is an integer number (1723465128).
Almost surely, 213170325481 is an apocalyptic number.
It is an amenable number.
13170325481 is a deficient number, since it is larger than the sum of its proper divisors (617395543).
13170325481 is a wasteful number, since it uses less digits than its factorization.
13170325481 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1865551.
The product of its (nonzero) digits is 20160, while the sum is 35.
The spelling of 13170325481 in words is "thirteen billion, one hundred seventy million, three hundred twenty-five thousand, four hundred eighty-one".
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