Base | Representation |
---|---|
bin | 11000100010000011… |
… | …01000011101010111 |
3 | 1020222212200212200112 |
4 | 30101001220131113 |
5 | 203433124324143 |
6 | 10014522233235 |
7 | 644243522603 |
oct | 142101503527 |
9 | 36885625615 |
10 | 13170542423 |
11 | 5649478505 |
12 | 267695581b |
13 | 131b813b8c |
14 | 8cd280503 |
15 | 5213dce18 |
hex | 311068757 |
13170542423 has 2 divisors, whose sum is σ = 13170542424. Its totient is φ = 13170542422.
The previous prime is 13170542383. The next prime is 13170542431. The reversal of 13170542423 is 32424507131.
It is a strong prime.
It is an emirp because it is prime and its reverse (32424507131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13170542423 - 216 = 13170476887 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13170542423.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13170542323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6585271211 + 6585271212.
It is an arithmetic number, because the mean of its divisors is an integer number (6585271212).
Almost surely, 213170542423 is an apocalyptic number.
13170542423 is a deficient number, since it is larger than the sum of its proper divisors (1).
13170542423 is an equidigital number, since it uses as much as digits as its factorization.
13170542423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 32.
The spelling of 13170542423 in words is "thirteen billion, one hundred seventy million, five hundred forty-two thousand, four hundred twenty-three".
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