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13171200000 = 21235573
BaseRepresentation
bin11000100010001000…
…01001000000000000
31020222220221021201020
430101010021000000
5203433311400000
610014544305440
7644252232000
oct142104110000
936886837636
1013171200000
115649887562
122677012280
13131b9b428a
148cd3b2000
155214bcba0
hex311109000

13171200000 has 624 divisors, whose sum is σ = 51190473600. Its totient is φ = 3010560000.

The previous prime is 13171199963. The next prime is 13171200001. The reversal of 13171200000 is 217131.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is not an unprimeable number, because it can be changed into a prime (13171200001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1881599997 + ... + 1881600003.

Almost surely, 213171200000 is an apocalyptic number.

13171200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13171200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (25595236800).

13171200000 is an abundant number, since it is smaller than the sum of its proper divisors (38019273600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13171200000 is an frugal number, since it uses more digits than its factorization.

13171200000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 73 (or 17 counting only the distinct ones).

The product of its (nonzero) digits is 42, while the sum is 15.

Adding to 13171200000 its reverse (217131), we get a palindrome (13171417131).

The spelling of 13171200000 in words is "thirteen billion, one hundred seventy-one million, two hundred thousand".