Base | Representation |
---|---|
bin | 10011001010101100010… |
… | …100101110110000101110 |
3 | 11122220210112012000112122 |
4 | 103022230110232300232 |
5 | 133040011140430032 |
6 | 2445031343232542 |
7 | 164106142456202 |
oct | 23125424566056 |
9 | 4586715160478 |
10 | 1317151108142 |
11 | 46866750a631 |
12 | 1933332a8752 |
13 | 9728c4b6c3c |
14 | 47a71360b02 |
15 | 243de9ea012 |
hex | 132ac52ec2e |
1317151108142 has 4 divisors (see below), whose sum is σ = 1975726662216. Its totient is φ = 658575554070.
The previous prime is 1317151108139. The next prime is 1317151108157. The reversal of 1317151108142 is 2418011517131.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×13171511081423 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 329287777034 + ... + 329287777037.
It is an arithmetic number, because the mean of its divisors is an integer number (493931665554).
Almost surely, 21317151108142 is an apocalyptic number.
1317151108142 is a deficient number, since it is larger than the sum of its proper divisors (658575554074).
1317151108142 is an equidigital number, since it uses as much as digits as its factorization.
1317151108142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 658575554073.
The product of its (nonzero) digits is 6720, while the sum is 35.
The spelling of 1317151108142 in words is "one trillion, three hundred seventeen billion, one hundred fifty-one million, one hundred eight thousand, one hundred forty-two".
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