Base | Representation |
---|---|
bin | 1011111110101100100001… |
… | …1100001001001011111111 |
3 | 1201122012112200120222202002 |
4 | 2333223020130021023333 |
5 | 3211301202013103044 |
6 | 44003002125052515 |
7 | 2526424545242033 |
oct | 277531034111377 |
9 | 51565480528662 |
10 | 13171732550399 |
11 | 42191117026a5 |
12 | 158892a6b713b |
13 | 747120847847 |
14 | 33772dc181c3 |
15 | 17c96116574e |
hex | bfac87092ff |
13171732550399 has 4 divisors (see below), whose sum is σ = 13182773400336. Its totient is φ = 13160691700464.
The previous prime is 13171732550393. The next prime is 13171732550441. The reversal of 13171732550399 is 99305523717131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13171732550399 - 228 = 13171464114943 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13171732550393) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5520423179 + ... + 5520425564.
It is an arithmetic number, because the mean of its divisors is an integer number (3295693350084).
Almost surely, 213171732550399 is an apocalyptic number.
13171732550399 is a deficient number, since it is larger than the sum of its proper divisors (11040849937).
13171732550399 is a wasteful number, since it uses less digits than its factorization.
13171732550399 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11040849936.
The product of its (nonzero) digits is 5358150, while the sum is 56.
The spelling of 13171732550399 in words is "thirteen trillion, one hundred seventy-one billion, seven hundred thirty-two million, five hundred fifty thousand, three hundred ninety-nine".
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