Base | Representation |
---|---|
bin | 1011111110101111101100… |
… | …0000001101111000101111 |
3 | 1201122021201210211222012211 |
4 | 2333223323000031320233 |
5 | 3211304421200231011 |
6 | 44003222231311251 |
7 | 2526454555644103 |
oct | 277537300157057 |
9 | 51567653758184 |
10 | 13172580867631 |
11 | 4219507544a19 |
12 | 1588b2681b527 |
13 | 747227516bc3 |
14 | 3377b075d903 |
15 | 17c9b0883b21 |
hex | bfafb00de2f |
13172580867631 has 8 divisors (see below), whose sum is σ = 13197339908480. Its totient is φ = 13147840069848.
The previous prime is 13172580867583. The next prime is 13172580867653. The reversal of 13172580867631 is 13676808527131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13172580867631 - 215 = 13172580834863 is a prime.
It is a super-2 number, since 2×131725808676312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13172580867431) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3114861 + ... + 6003958.
It is an arithmetic number, because the mean of its divisors is an integer number (1649667488560).
Almost surely, 213172580867631 is an apocalyptic number.
13172580867631 is a deficient number, since it is larger than the sum of its proper divisors (24759040849).
13172580867631 is an equidigital number, since it uses as much as digits as its factorization.
13172580867631 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9121533.
The product of its (nonzero) digits is 10160640, while the sum is 58.
The spelling of 13172580867631 in words is "thirteen trillion, one hundred seventy-two billion, five hundred eighty million, eight hundred sixty-seven thousand, six hundred thirty-one".
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