13181491441 has 2 divisors, whose sum is σ = 13181491442. Its totient is φ = 13181491440.

The previous prime is 13181491397. The next prime is 13181491451. The reversal of 13181491441 is 14419418131.

13181491441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12683264400 + 498227041 = 112620^2 + 22321^2 .

It is a cyclic number.

It is not a de Polignac number, because 13181491441 - 2¹⁵ = 13181458673 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13181491441.

It is not a weakly prime, because it can be changed into another prime (13181491451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6590745720 + 6590745721.

It is an arithmetic number, because the mean of its divisors is an integer number (6590745721).

Almost surely, 2^13181491441 is an apocalyptic number.

It is an amenable number.

13181491441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13181491441 is an equidigital number, since it uses as much as digits as its factorization.

13181491441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 13824, while the sum is 37.

The spelling of 13181491441 in words is "thirteen billion, one hundred eighty-one million, four hundred ninety-one thousand, four hundred forty-one".