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1318265077343 is a prime number
BaseRepresentation
bin10011001011101110101…
…110001011111001011111
311200000200011022112000012
4103023232232023321133
5133044301324433333
62445334055353435
7164145560162624
oct23135656137137
94600604275005
101318265077343
114690892a6135
121935a438287b
1397409219006
1447b3929834b
15244576dee48
hex132eeb8be5f

1318265077343 has 2 divisors, whose sum is σ = 1318265077344. Its totient is φ = 1318265077342.

The previous prime is 1318265077279. The next prime is 1318265077361. The reversal of 1318265077343 is 3437705628131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1318265077343 - 26 = 1318265077279 is a prime.

It is a super-3 number, since 3×13182650773433 (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1318265077291 and 1318265077300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1318265047343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 659132538671 + 659132538672.

It is an arithmetic number, because the mean of its divisors is an integer number (659132538672).

Almost surely, 21318265077343 is an apocalyptic number.

1318265077343 is a deficient number, since it is larger than the sum of its proper divisors (1).

1318265077343 is an equidigital number, since it uses as much as digits as its factorization.

1318265077343 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2540160, while the sum is 50.

The spelling of 1318265077343 in words is "one trillion, three hundred eighteen billion, two hundred sixty-five million, seventy-seven thousand, three hundred forty-three".