1319103011 has 2 divisors, whose sum is σ = 1319103012. Its totient is φ = 1319103010.

The previous prime is 1319102999. The next prime is 1319103013. The reversal of 1319103011 is 1103019131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1319103011 is a prime.

It is a super-3 number, since 3×1319103011³ (a number of 28 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 1319103013, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1319103013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 659551505 + 659551506.

It is an arithmetic number, because the mean of its divisors is an integer number (659551506).

Almost surely, 2^1319103011 is an apocalyptic number.

1319103011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1319103011 is an equidigital number, since it uses as much as digits as its factorization.

1319103011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 20.

The square root of 1319103011 is about 36319.4577465028. The cubic root of 1319103011 is about 1096.7127788722.

The spelling of 1319103011 in words is "one billion, three hundred nineteen million, one hundred three thousand, eleven".