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13193854143 = 34397951381
BaseRepresentation
bin11000100100110101…
…00011110010111111
31021001111120020100120
430102122203302333
5204010111313033
610021114030023
7644645624031
oct142232436277
937044506316
1013193854143
11566064a998
122682718313
1313235b67b2
148d23cbc51
155234951b3
hex3126a3cbf

13193854143 has 4 divisors (see below), whose sum is σ = 17591805528. Its totient is φ = 8795902760.

The previous prime is 13193854109. The next prime is 13193854171. The reversal of 13193854143 is 34145839131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34145839131 = 311381946377.

It is a cyclic number.

It is not a de Polignac number, because 13193854143 - 232 = 8898886847 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13193854095 and 13193854104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13193854183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2198975688 + ... + 2198975693.

It is an arithmetic number, because the mean of its divisors is an integer number (4397951382).

Almost surely, 213193854143 is an apocalyptic number.

13193854143 is a deficient number, since it is larger than the sum of its proper divisors (4397951385).

13193854143 is an equidigital number, since it uses as much as digits as its factorization.

13193854143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4397951384.

The product of its digits is 155520, while the sum is 42.

The spelling of 13193854143 in words is "thirteen billion, one hundred ninety-three million, eight hundred fifty-four thousand, one hundred forty-three".

Divisors: 1 3 4397951381 13193854143