Base | Representation |
---|---|
bin | 11000100101011111… |
… | …11110011000010111 |
3 | 1021001220010110012020 |
4 | 30102233332120113 |
5 | 204013030434210 |
6 | 10021434224223 |
7 | 645044425104 |
oct | 142257763027 |
9 | 37056113166 |
10 | 13199468055 |
11 | 5663834794 |
12 | 2684585073 |
13 | 1324800b37 |
14 | 8d304daab |
15 | 523c03770 |
hex | 312bfe617 |
13199468055 has 32 divisors (see below), whose sum is σ = 22354963200. Its totient is φ = 6631921152.
The previous prime is 13199468053. The next prime is 13199468069. The reversal of 13199468055 is 55086499131.
It is not a de Polignac number, because 13199468055 - 21 = 13199468053 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13199467989 and 13199468007.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13199468053) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 78354 + ... + 180383.
It is an arithmetic number, because the mean of its divisors is an integer number (698592600).
Almost surely, 213199468055 is an apocalyptic number.
13199468055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13199468055 is a deficient number, since it is larger than the sum of its proper divisors (9155495145).
13199468055 is a wasteful number, since it uses less digits than its factorization.
13199468055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 258943.
The product of its (nonzero) digits is 1166400, while the sum is 51.
The spelling of 13199468055 in words is "thirteen billion, one hundred ninety-nine million, four hundred sixty-eight thousand, fifty-five".
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