Base | Representation |
---|---|
bin | 111101011101110100… |
… | …1001000001111110101 |
3 | 110121201002220110121101 |
4 | 1322323221020033311 |
5 | 4130312231434312 |
6 | 140345540450101 |
7 | 12352004114554 |
oct | 1727351101765 |
9 | 417632813541 |
10 | 131997139957 |
11 | 50a85a42a21 |
12 | 216b96a9931 |
13 | c5a788a157 |
14 | 656281bd9b |
15 | 367835da57 |
hex | 1ebba483f5 |
131997139957 has 2 divisors, whose sum is σ = 131997139958. Its totient is φ = 131997139956.
The previous prime is 131997139951. The next prime is 131997139961. The reversal of 131997139957 is 759931799131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 109379687076 + 22617452881 = 330726^2 + 150391^2 .
It is a cyclic number.
It is not a de Polignac number, because 131997139957 - 219 = 131996615669 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131997139951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65998569978 + 65998569979.
It is an arithmetic number, because the mean of its divisors is an integer number (65998569979).
Almost surely, 2131997139957 is an apocalyptic number.
It is an amenable number.
131997139957 is a deficient number, since it is larger than the sum of its proper divisors (1).
131997139957 is an equidigital number, since it uses as much as digits as its factorization.
131997139957 is an evil number, because the sum of its binary digits is even.
The product of its digits is 14467005, while the sum is 64.
The spelling of 131997139957 in words is "one hundred thirty-one billion, nine hundred ninety-seven million, one hundred thirty-nine thousand, nine hundred fifty-seven".
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