Base | Representation |
---|---|
bin | 11110000000110101101100… |
… | …010111010000100010011011 |
3 | 122022100222121121101200220102 |
4 | 132000311230113100202123 |
5 | 114300133022233204342 |
6 | 1144423305301050015 |
7 | 36542421313652213 |
oct | 3600655427204233 |
9 | 568328547350812 |
10 | 131999047944347 |
11 | 390715333a1561 |
12 | 1297a3720b690b |
13 | 58865c27c7bcc |
14 | 2484b06421243 |
15 | 103d8e8bb5832 |
hex | 780d6c5d089b |
131999047944347 has 4 divisors (see below), whose sum is σ = 131999157297456. Its totient is φ = 131998938591240.
The previous prime is 131999047944319. The next prime is 131999047944371. The reversal of 131999047944347 is 743449740999131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131999047944347 - 236 = 131930328467611 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131999047944307) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52845479 + ... + 55286912.
It is an arithmetic number, because the mean of its divisors is an integer number (32999789324364).
Almost surely, 2131999047944347 is an apocalyptic number.
131999047944347 is a deficient number, since it is larger than the sum of its proper divisors (109353109).
131999047944347 is a wasteful number, since it uses less digits than its factorization.
131999047944347 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 109353108.
The product of its (nonzero) digits is 740710656, while the sum is 74.
The spelling of 131999047944347 in words is "one hundred thirty-one trillion, nine hundred ninety-nine billion, forty-seven million, nine hundred forty-four thousand, three hundred forty-seven".
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