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132000032011 = 6121391101161
BaseRepresentation
bin111101011101111010…
…0001010010100001011
3110121201022100101202111
41322323310022110023
54130314002011021
6140350122443151
712352040521321
oct1727364122413
9417638311674
10132000032011
1150a87638851
12216ba6634b7
13c5a8360623
146562d71d11
1536787308e1
hex1ebbd0a50b

132000032011 has 8 divisors (see below), whose sum is σ = 134171565248. Its totient is φ = 129828744000.

The previous prime is 132000032009. The next prime is 132000032029. The reversal of 132000032011 is 110230000231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 132000032011 - 21 = 132000032009 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132000031982 and 132000032000.

It is not an unprimeable number, because it can be changed into a prime (132000032611) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1254271 + ... + 1355431.

It is an arithmetic number, because the mean of its divisors is an integer number (16771445656).

Almost surely, 2132000032011 is an apocalyptic number.

132000032011 is a deficient number, since it is larger than the sum of its proper divisors (2171533237).

132000032011 is a wasteful number, since it uses less digits than its factorization.

132000032011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 122613.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 132000032011 its reverse (110230000231), we get a palindrome (242230032242).

The spelling of 132000032011 in words is "one hundred thirty-two billion, thirty-two thousand, eleven".

Divisors: 1 61 21391 101161 1304851 6170821 2163934951 132000032011