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13200041143181 is a prime number
BaseRepresentation
bin1100000000010101111111…
…0000110110101110001101
31201201220121120012111121102
43000011133300312232031
53212232141013040211
644024003140312445
72531446216304354
oct300053760665615
951656546174542
1013200041143181
11422a119112422
12159230b0a2725
137499b2681569
14338c5777699b
1517d56b536a3b
hexc015fc36b8d

13200041143181 has 2 divisors, whose sum is σ = 13200041143182. Its totient is φ = 13200041143180.

The previous prime is 13200041143117. The next prime is 13200041143297. The reversal of 13200041143181 is 18134114000231.

13200041143181 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10205047477156 + 2994993666025 = 3194534^2 + 1730605^2 .

It is a cyclic number.

It is not a de Polignac number, because 13200041143181 - 26 = 13200041143117 is a prime.

It is a super-2 number, since 2×132000411431812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13200041143111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600020571590 + 6600020571591.

It is an arithmetic number, because the mean of its divisors is an integer number (6600020571591).

Almost surely, 213200041143181 is an apocalyptic number.

It is an amenable number.

13200041143181 is a deficient number, since it is larger than the sum of its proper divisors (1).

13200041143181 is an equidigital number, since it uses as much as digits as its factorization.

13200041143181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 29.

The spelling of 13200041143181 in words is "thirteen trillion, two hundred billion, forty-one million, one hundred forty-three thousand, one hundred eighty-one".