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13200043140422 = 26600021570211
BaseRepresentation
bin1100000000010101111111…
…1000011110010101000110
31201201220121200221222022022
43000011133320132111012
53212232142020443142
644024003251203142
72531446242263255
oct300053770362506
951656550858268
1013200043140422
11422a11a256a36
12159230b8a64b2
137499b2c00668
14338c57b3679c
1517d56b7cd6d2
hexc015fe1e546

13200043140422 has 4 divisors (see below), whose sum is σ = 19800064710636. Its totient is φ = 6600021570210.

The previous prime is 13200043140421. The next prime is 13200043140443. The reversal of 13200043140422 is 22404134000231.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×132000431404222 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13200043140391 and 13200043140400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13200043140421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3300010785104 + ... + 3300010785107.

It is an arithmetic number, because the mean of its divisors is an integer number (4950016177659).

Almost surely, 213200043140422 is an apocalyptic number.

13200043140422 is a deficient number, since it is larger than the sum of its proper divisors (6600021570214).

13200043140422 is an equidigital number, since it uses as much as digits as its factorization.

13200043140422 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6600021570213.

The product of its (nonzero) digits is 4608, while the sum is 26.

Adding to 13200043140422 its reverse (22404134000231), we get a palindrome (35604177140653).

The spelling of 13200043140422 in words is "thirteen trillion, two hundred billion, forty-three million, one hundred forty thousand, four hundred twenty-two".

Divisors: 1 2 6600021570211 13200043140422