13200101131121 has 4 divisors (see below), whose sum is σ = 13295065887600. Its totient is φ = 13105136374644.

The previous prime is 13200101131099. The next prime is 13200101131127. The reversal of 13200101131121 is 12113110100231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13200101131121 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 13200101131121.

It is not an unprimeable number, because it can be changed into a prime (13200101131127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47482378031 + ... + 47482378308.

It is an arithmetic number, because the mean of its divisors is an integer number (3323766471900).

Almost surely, 2^{13200101131121} is an apocalyptic number.

It is an amenable number.

13200101131121 is a deficient number, since it is larger than the sum of its proper divisors (94964756479).

13200101131121 is an equidigital number, since it uses as much as digits as its factorization.

13200101131121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 94964756478.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 13200101131121 its reverse (12113110100231), we get a palindrome (25313211231352).

The spelling of 13200101131121 in words is "thirteen trillion, two hundred billion, one hundred one million, one hundred thirty-one thousand, one hundred twenty-one".