Base | Representation |
---|---|
bin | 11000100101100100… |
… | …11110100111110001 |
3 | 1021001221100210112100 |
4 | 30102302132213301 |
5 | 204013212440101 |
6 | 10021500251013 |
7 | 645053130462 |
oct | 142262364761 |
9 | 37057323470 |
10 | 13200124401 |
11 | 5664142922 |
12 | 2684840a69 |
13 | 13249a07c9 |
14 | 8d3180d69 |
15 | 523cd2e86 |
hex | 312c9e9f1 |
13200124401 has 24 divisors (see below), whose sum is σ = 19396362024. Its totient is φ = 8649273600.
The previous prime is 13200124393. The next prime is 13200124459. The reversal of 13200124401 is 10442100231.
13200124401 is a `hidden beast` number, since 13 + 200 + 12 + 440 + 1 = 666.
It can be written as a sum of positive squares in 4 ways, for example, as 4928040000 + 8272084401 = 70200^2 + 90951^2 .
It is not a de Polignac number, because 13200124401 - 23 = 13200124393 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13200124001) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 71535 + ... + 177531.
It is an arithmetic number, because the mean of its divisors is an integer number (808181751).
Almost surely, 213200124401 is an apocalyptic number.
It is an amenable number.
13200124401 is a deficient number, since it is larger than the sum of its proper divisors (6196237623).
13200124401 is a wasteful number, since it uses less digits than its factorization.
13200124401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 106241 (or 106238 counting only the distinct ones).
The product of its (nonzero) digits is 192, while the sum is 18.
Adding to 13200124401 its reverse (10442100231), we get a palindrome (23642224632).
The spelling of 13200124401 in words is "thirteen billion, two hundred million, one hundred twenty-four thousand, four hundred one".
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