Base | Representation |
---|---|
bin | 1100000000010110010100… |
… | …1111101100010111010111 |
3 | 1201201220211222021001220020 |
4 | 3000011211033230113113 |
5 | 3212232333034111203 |
6 | 44024020223440223 |
7 | 2531451414114003 |
oct | 300054517542727 |
9 | 51656758231806 |
10 | 13200133113303 |
11 | 422a166019994 |
12 | 1592335a56073 |
13 | 7499c8743156 |
14 | 338c65a77703 |
15 | 17d574652153 |
hex | c01653ec5d7 |
13200133113303 has 64 divisors (see below), whose sum is σ = 18809300044800. Its totient is φ = 8220580945920.
The previous prime is 13200133113263. The next prime is 13200133113319. The reversal of 13200133113303 is 30331133100231.
13200133113303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13200133113303 - 26 = 13200133113239 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13200133113203) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 210252225 + ... + 210314997.
It is an arithmetic number, because the mean of its divisors is an integer number (293895313200).
Almost surely, 213200133113303 is an apocalyptic number.
13200133113303 is a deficient number, since it is larger than the sum of its proper divisors (5609166931497).
13200133113303 is a wasteful number, since it uses less digits than its factorization.
13200133113303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 63512.
The product of its (nonzero) digits is 1458, while the sum is 24.
Adding to 13200133113303 its reverse (30331133100231), we get a palindrome (43531266213534).
The spelling of 13200133113303 in words is "thirteen trillion, two hundred billion, one hundred thirty-three million, one hundred thirteen thousand, three hundred three".
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