13200211001401 has 4 divisors (see below), whose sum is σ = 13217376426100. Its totient is φ = 13183045576704.

The previous prime is 13200211001371. The next prime is 13200211001407. The reversal of 13200211001401 is 10410011200231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3345314160400 + 9854896841001 = 1829020^2 + 3139251^2 .

It is a cyclic number.

It is not a de Polignac number, because 13200211001401 - 2³³ = 13191621066809 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13200211001407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8582711196 + ... + 8582712733.

It is an arithmetic number, because the mean of its divisors is an integer number (3304344106525).

Almost surely, 2^{13200211001401} is an apocalyptic number.

It is an amenable number.

13200211001401 is a deficient number, since it is larger than the sum of its proper divisors (17165424699).

13200211001401 is an equidigital number, since it uses as much as digits as its factorization.

13200211001401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17165424698.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 13200211001401 its reverse (10410011200231), we get a palindrome (23610222201632).

The spelling of 13200211001401 in words is "thirteen trillion, two hundred billion, two hundred eleven million, one thousand, four hundred one".