1320021142241 has 4 divisors (see below), whose sum is σ = 1342394382000. Its totient is φ = 1297647902484.

The previous prime is 1320021142229. The next prime is 1320021142283. The reversal of 1320021142241 is 1422411200231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1320021142241 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1320021142201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11186619791 + ... + 11186619908.

It is an arithmetic number, because the mean of its divisors is an integer number (335598595500).

Almost surely, 2^{1320021142241} is an apocalyptic number.

It is an amenable number.

1320021142241 is a deficient number, since it is larger than the sum of its proper divisors (22373239759).

1320021142241 is an equidigital number, since it uses as much as digits as its factorization.

1320021142241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22373239758.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 1320021142241 its reverse (1422411200231), we get a palindrome (2742432342472).

The spelling of 1320021142241 in words is "one trillion, three hundred twenty billion, twenty-one million, one hundred forty-two thousand, two hundred forty-one".