1320032040124 has 24 divisors (see below), whose sum is σ = 2689876613088. Its totient is φ = 555053903040.

The previous prime is 1320032040079. The next prime is 1320032040167. The reversal of 1320032040124 is 4210402300231.

It is a junction number, because it is equal to n+sod(n) for n = 1320032040095 and 1320032040104.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 444753247 + ... + 444756214.

It is an arithmetic number, because the mean of its divisors is an integer number (112078192212).

Almost surely, 2^{1320032040124} is an apocalyptic number.

1320032040124 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

It is an amenable number.

1320032040124 is an abundant number, since it is smaller than the sum of its proper divisors (1369844572964).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1320032040124 is a wasteful number, since it uses less digits than its factorization.

1320032040124 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 889509525 (or 889509523 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 1320032040124 its reverse (4210402300231), we get a palindrome (5530434340355).

The spelling of 1320032040124 in words is "one trillion, three hundred twenty billion, thirty-two million, forty thousand, one hundred twenty-four".