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132003221333124 = 22374323148006249
BaseRepresentation
bin11110000000111001100101…
…000111011110010010000100
3122022101101101110100211001010
4132000321211013132102010
5114300220044130124444
61144425235343202220
736542626611120351
oct3600714507362204
9568341343324033
10132003221333124
1139073285142299
121297b1378a6370
135886b0931721b
142484dc07cb628
15103da9028a2b9
hex780e651de484

132003221333124 has 24 divisors (see below), whose sum is σ = 308011662700000. Its totient is φ = 44000481455424.

The previous prime is 132003221333083. The next prime is 132003221333149. The reversal of 132003221333124 is 421333122300231.

It is a junction number, because it is equal to n+sod(n) for n = 132003221333091 and 132003221333100.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 73111249 + ... + 74895000.

Almost surely, 2132003221333124 is an apocalyptic number.

It is an amenable number.

132003221333124 is an abundant number, since it is smaller than the sum of its proper divisors (176008441366876).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132003221333124 is a wasteful number, since it uses less digits than its factorization.

132003221333124 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 148080579 (or 148080577 counting only the distinct ones).

The product of its (nonzero) digits is 15552, while the sum is 30.

Adding to 132003221333124 its reverse (421333122300231), we get a palindrome (553336343633355).

The spelling of 132003221333124 in words is "one hundred thirty-two trillion, three billion, two hundred twenty-one million, three hundred thirty-three thousand, one hundred twenty-four".

Divisors: 1 2 3 4 6 12 74323 148646 222969 297292 445938 891876 148006249 296012498 444018747 592024996 888037494 1776074988 11000268444427 22000536888854 33000805333281 44001073777708 66001610666562 132003221333124