Base | Representation |
---|---|
bin | 11110000000111001100101… |
… | …000111011110010010000100 |
3 | 122022101101101110100211001010 |
4 | 132000321211013132102010 |
5 | 114300220044130124444 |
6 | 1144425235343202220 |
7 | 36542626611120351 |
oct | 3600714507362204 |
9 | 568341343324033 |
10 | 132003221333124 |
11 | 39073285142299 |
12 | 1297b1378a6370 |
13 | 5886b0931721b |
14 | 2484dc07cb628 |
15 | 103da9028a2b9 |
hex | 780e651de484 |
132003221333124 has 24 divisors (see below), whose sum is σ = 308011662700000. Its totient is φ = 44000481455424.
The previous prime is 132003221333083. The next prime is 132003221333149. The reversal of 132003221333124 is 421333122300231.
It is a junction number, because it is equal to n+sod(n) for n = 132003221333091 and 132003221333100.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 73111249 + ... + 74895000.
Almost surely, 2132003221333124 is an apocalyptic number.
It is an amenable number.
132003221333124 is an abundant number, since it is smaller than the sum of its proper divisors (176008441366876).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132003221333124 is a wasteful number, since it uses less digits than its factorization.
132003221333124 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 148080579 (or 148080577 counting only the distinct ones).
The product of its (nonzero) digits is 15552, while the sum is 30.
Adding to 132003221333124 its reverse (421333122300231), we get a palindrome (553336343633355).
The spelling of 132003221333124 in words is "one hundred thirty-two trillion, three billion, two hundred twenty-one million, three hundred thirty-three thousand, one hundred twenty-four".
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