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132003333403247 is a prime number
BaseRepresentation
bin11110000000111001101011…
…110010111111001001101111
3122022101101200021020120100102
4132000321223302333021233
5114300220311322400442
61144425254425221315
736542632441523405
oct3600715362771157
9568341607216312
10132003333403247
1139073332428229
121297b16933183b
135886b265c58c7
142484dd1641475
15103da9a026232
hex780e6bcbf26f

132003333403247 has 2 divisors, whose sum is σ = 132003333403248. Its totient is φ = 132003333403246.

The previous prime is 132003333403243. The next prime is 132003333403399. The reversal of 132003333403247 is 742304333300231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 132003333403247 - 22 = 132003333403243 is a prime.

It is a super-2 number, since 2×1320033334032472 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 132003333403247.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132003333403243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66001666701623 + 66001666701624.

It is an arithmetic number, because the mean of its divisors is an integer number (66001666701624).

Almost surely, 2132003333403247 is an apocalyptic number.

132003333403247 is a deficient number, since it is larger than the sum of its proper divisors (1).

132003333403247 is an equidigital number, since it uses as much as digits as its factorization.

132003333403247 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 326592, while the sum is 38.

Adding to 132003333403247 its reverse (742304333300231), we get a palindrome (874307666703478).

The spelling of 132003333403247 in words is "one hundred thirty-two trillion, three billion, three hundred thirty-three million, four hundred three thousand, two hundred forty-seven".