Base | Representation |
---|---|
bin | 111101011110000000… |
… | …1000001101011101001 |
3 | 110121201112200201222021 |
4 | 1322330001001223221 |
5 | 4130320332421041 |
6 | 140350323024441 |
7 | 12352111265602 |
oct | 1727401015351 |
9 | 417645621867 |
10 | 132003404521 |
11 | 50a8953164a |
12 | 216bb80b121 |
13 | c5a8c716b1 |
14 | 65635acda9 |
15 | 3678b99cd1 |
hex | 1ebc041ae9 |
132003404521 has 4 divisors (see below), whose sum is σ = 132024602500. Its totient is φ = 131982206544.
The previous prime is 132003404503. The next prime is 132003404527. The reversal of 132003404521 is 125404300231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 106268828121 + 25734576400 = 325989^2 + 160420^2 .
It is a cyclic number.
It is not a de Polignac number, because 132003404521 - 211 = 132003402473 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132003404527) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10589646 + ... + 10602103.
It is an arithmetic number, because the mean of its divisors is an integer number (33006150625).
Almost surely, 2132003404521 is an apocalyptic number.
It is an amenable number.
132003404521 is a deficient number, since it is larger than the sum of its proper divisors (21197979).
132003404521 is an equidigital number, since it uses as much as digits as its factorization.
132003404521 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21197978.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 132003404521 its reverse (125404300231), we get a palindrome (257407704752).
The spelling of 132003404521 in words is "one hundred thirty-two billion, three million, four hundred four thousand, five hundred twenty-one".
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