125404300231 has 8 divisors (see below), whose sum is σ = 151749741600. Its totient is φ = 101166494208.

The previous prime is 125404300223. The next prime is 125404300291. The reversal of 125404300231 is 132003404521.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 125404300231 - 2³ = 125404300223 is a prime.

It is a super-2 number, since 2×125404300231² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 125404300196 and 125404300205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (125404300211) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 526908706 + ... + 526908943.

It is an arithmetic number, because the mean of its divisors is an integer number (18968717700).

Almost surely, 2^125404300231 is an apocalyptic number.

125404300231 is a deficient number, since it is larger than the sum of its proper divisors (26345441369).

125404300231 is a wasteful number, since it uses less digits than its factorization.

125404300231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1053817673.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 125404300231 its reverse (132003404521), we get a palindrome (257407704752).

The spelling of 125404300231 in words is "one hundred twenty-five billion, four hundred four million, three hundred thousand, two hundred thirty-one".