Base | Representation |
---|---|
bin | 1100000000010111000110… |
… | …1101000010111001110101 |
3 | 1201201221101112120102220221 |
4 | 3000011301231002321311 |
5 | 3212233300041300024 |
6 | 44024053051454341 |
7 | 2531456532552634 |
oct | 300056155027165 |
9 | 51657345512827 |
10 | 13200342134389 |
11 | 422a263003593 |
12 | 1592393a573b1 |
13 | 749a2cb38577 |
14 | 338c8572751b |
15 | 17d587b8e3e4 |
hex | c0171b42e75 |
13200342134389 has 2 divisors, whose sum is σ = 13200342134390. Its totient is φ = 13200342134388.
The previous prime is 13200342134299. The next prime is 13200342134429. The reversal of 13200342134389 is 98343124300231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13195855412100 + 4486722289 = 3632610^2 + 66983^2 .
It is a cyclic number.
It is not a de Polignac number, because 13200342134389 - 215 = 13200342101621 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13200342734389) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600171067194 + 6600171067195.
It is an arithmetic number, because the mean of its divisors is an integer number (6600171067195).
Almost surely, 213200342134389 is an apocalyptic number.
It is an amenable number.
13200342134389 is a deficient number, since it is larger than the sum of its proper divisors (1).
13200342134389 is an equidigital number, since it uses as much as digits as its factorization.
13200342134389 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 373248, while the sum is 43.
The spelling of 13200342134389 in words is "thirteen trillion, two hundred billion, three hundred forty-two million, one hundred thirty-four thousand, three hundred eighty-nine".
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