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1320041000321 is a prime number
BaseRepresentation
bin10011001101011000100…
…100110010110110000001
311200012020221000202100022
4103031120210302312001
5133111420444002241
62450230215503225
7164240563240631
oct23153044626601
94605227022308
101320041000321
1146990a80537a
121939bb087b15
1397630129004
1447c670a46c1
152450d58e54b
hex13358932d81

1320041000321 has 2 divisors, whose sum is σ = 1320041000322. Its totient is φ = 1320041000320.

The previous prime is 1320041000303. The next prime is 1320041000359. The reversal of 1320041000321 is 1230001400231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 903809574721 + 416231425600 = 950689^2 + 645160^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1320041000321 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1320041000321.

It is not a weakly prime, because it can be changed into another prime (1320041002321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660020500160 + 660020500161.

It is an arithmetic number, because the mean of its divisors is an integer number (660020500161).

Almost surely, 21320041000321 is an apocalyptic number.

It is an amenable number.

1320041000321 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320041000321 is an equidigital number, since it uses as much as digits as its factorization.

1320041000321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 1320041000321 its reverse (1230001400231), we get a palindrome (2550042400552).

The spelling of 1320041000321 in words is "one trillion, three hundred twenty billion, forty-one million, three hundred twenty-one", and thus it is an aban number.