Base | Representation |
---|---|
bin | 11000100101100111… |
… | …01010001101100001 |
3 | 1021001221221112020121 |
4 | 30102303222031201 |
5 | 204013302342032 |
6 | 10021511040241 |
7 | 645055560241 |
oct | 142263521541 |
9 | 37057845217 |
10 | 13200434017 |
11 | 5664334501 |
12 | 2684970081 |
13 | 1324a7b704 |
14 | 8d3221b21 |
15 | 523d44a97 |
hex | 312cea361 |
13200434017 has 2 divisors, whose sum is σ = 13200434018. Its totient is φ = 13200434016.
The previous prime is 13200433997. The next prime is 13200434041. The reversal of 13200434017 is 71043400231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12950667601 + 249766416 = 113801^2 + 15804^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13200434017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13200433982 and 13200434000.
It is not a weakly prime, because it can be changed into another prime (13200434047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600217008 + 6600217009.
It is an arithmetic number, because the mean of its divisors is an integer number (6600217009).
Almost surely, 213200434017 is an apocalyptic number.
It is an amenable number.
13200434017 is a deficient number, since it is larger than the sum of its proper divisors (1).
13200434017 is an equidigital number, since it uses as much as digits as its factorization.
13200434017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 25.
Adding to 13200434017 its reverse (71043400231), we get a palindrome (84243834248).
The spelling of 13200434017 in words is "thirteen billion, two hundred million, four hundred thirty-four thousand, seventeen".
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