132010020011 has 2 divisors, whose sum is σ = 132010020012. Its totient is φ = 132010020010.

The previous prime is 132010019959. The next prime is 132010020101. The reversal of 132010020011 is 110020010231.

Together with next prime (132010020101) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132010020011 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132010019974 and 132010020001.

It is not a weakly prime, because it can be changed into another prime (132010020211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66005010005 + 66005010006.

It is an arithmetic number, because the mean of its divisors is an integer number (66005010006).

Almost surely, 2^132010020011 is an apocalyptic number.

132010020011 is a deficient number, since it is larger than the sum of its proper divisors (1).

132010020011 is an equidigital number, since it uses as much as digits as its factorization.

132010020011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 132010020011 its reverse (110020010231), we get a palindrome (242030030242).

The spelling of 132010020011 in words is "one hundred thirty-two billion, ten million, twenty thousand, eleven".