Base | Representation |
---|---|
bin | 111101011110001101… |
… | …1101101111011001111 |
3 | 110121202000212020000011 |
4 | 1322330123231323033 |
5 | 4130324130321422 |
6 | 140351133014051 |
7 | 12352224620116 |
oct | 1727433557317 |
9 | 417660766004 |
10 | 132010401487 |
11 | 50a92480568 |
12 | 21702024327 |
13 | c5aa551403 |
14 | 65644b0c7d |
15 | 36795cd077 |
hex | 1ebc6edecf |
132010401487 has 2 divisors, whose sum is σ = 132010401488. Its totient is φ = 132010401486.
The previous prime is 132010401437. The next prime is 132010401527. The reversal of 132010401487 is 784104010231.
It is a strong prime.
It is an emirp because it is prime and its reverse (784104010231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132010401487 - 211 = 132010399439 is a prime.
It is a super-2 number, since 2×1320104014872 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132010401437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66005200743 + 66005200744.
It is an arithmetic number, because the mean of its divisors is an integer number (66005200744).
Almost surely, 2132010401487 is an apocalyptic number.
132010401487 is a deficient number, since it is larger than the sum of its proper divisors (1).
132010401487 is an equidigital number, since it uses as much as digits as its factorization.
132010401487 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5376, while the sum is 31.
The spelling of 132010401487 in words is "one hundred thirty-two billion, ten million, four hundred one thousand, four hundred eighty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •