Base | Representation |
---|---|
bin | 11110000001000000110100… |
… | …110000100101001000010111 |
3 | 122022102010110120020000020001 |
4 | 132001000310300211020113 |
5 | 114300332011442210322 |
6 | 1144433003254152131 |
7 | 36543323433265153 |
oct | 3601006460451027 |
9 | 568363416200201 |
10 | 132010999960087 |
11 | 39076606a59916 |
12 | 12980748952647 |
13 | 5887778a2b981 |
14 | 248551b90c063 |
15 | 103dd98108827 |
hex | 781034c25217 |
132010999960087 has 2 divisors, whose sum is σ = 132010999960088. Its totient is φ = 132010999960086.
The previous prime is 132010999960079. The next prime is 132010999960117. The reversal of 132010999960087 is 780069999010231.
It is a weak prime.
It is an emirp because it is prime and its reverse (780069999010231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132010999960087 - 23 = 132010999960079 is a prime.
It is a super-2 number, since 2×1320109999600872 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132010999960027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66005499980043 + 66005499980044.
It is an arithmetic number, because the mean of its divisors is an integer number (66005499980044).
Almost surely, 2132010999960087 is an apocalyptic number.
132010999960087 is a deficient number, since it is larger than the sum of its proper divisors (1).
132010999960087 is an equidigital number, since it uses as much as digits as its factorization.
132010999960087 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13226976, while the sum is 64.
The spelling of 132010999960087 in words is "one hundred thirty-two trillion, ten billion, nine hundred ninety-nine million, nine hundred sixty thousand, eighty-seven".
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