13201102403 has 4 divisors (see below), whose sum is σ = 13626944448. Its totient is φ = 12775260360.

The previous prime is 13201102399. The next prime is 13201102433. The reversal of 13201102403 is 30420110231.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30420110231 = 7 ⋅4345730033.

It is a cyclic number.

It is not a de Polignac number, because 13201102403 - 2² = 13201102399 is a prime.

It is a super-3 number, since 3×13201102403³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13201102433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 212920976 + ... + 212921037.

It is an arithmetic number, because the mean of its divisors is an integer number (3406736112).

Almost surely, 2^13201102403 is an apocalyptic number.

13201102403 is a deficient number, since it is larger than the sum of its proper divisors (425842045).

13201102403 is an equidigital number, since it uses as much as digits as its factorization.

13201102403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 425842044.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 13201102403 its reverse (30420110231), we get a palindrome (43621212634).

The spelling of 13201102403 in words is "thirteen billion, two hundred one million, one hundred two thousand, four hundred three".