13201111120123 has 4 divisors (see below), whose sum is σ = 13523089440168. Its totient is φ = 12879132800080.

The previous prime is 13201111120117. The next prime is 13201111120129. The reversal of 13201111120123 is 32102111110231.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13201111120117) and next prime (13201111120129).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13201111120123 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13201111120123.

It is not an unprimeable number, because it can be changed into a prime (13201111120129) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160989159961 + ... + 160989160042.

It is an arithmetic number, because the mean of its divisors is an integer number (3380772360042).

Almost surely, 2^{13201111120123} is an apocalyptic number.

13201111120123 is a deficient number, since it is larger than the sum of its proper divisors (321978320045).

13201111120123 is an equidigital number, since it uses as much as digits as its factorization.

13201111120123 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 321978320044.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 13201111120123 its reverse (32102111110231), we get a palindrome (45303222230354).

The spelling of 13201111120123 in words is "thirteen trillion, two hundred one billion, one hundred eleven million, one hundred twenty thousand, one hundred twenty-three".