Base | Representation |
---|---|
bin | 11000100101101100… |
… | …10100011100110111 |
3 | 1021002000020221202121 |
4 | 30102312110130313 |
5 | 204013442200234 |
6 | 10021534020411 |
7 | 645064523215 |
oct | 142266243467 |
9 | 37060227677 |
10 | 13201131319 |
11 | 5664770392 |
12 | 2685047707 |
13 | 1324c63c0c |
14 | 8d3363cb5 |
15 | 523e314b4 |
hex | 312d94737 |
13201131319 has 2 divisors, whose sum is σ = 13201131320. Its totient is φ = 13201131318.
The previous prime is 13201131311. The next prime is 13201131331. The reversal of 13201131319 is 91313110231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13201131319 - 23 = 13201131311 is a prime.
It is a super-2 number, since 2×132011313192 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13201131293 and 13201131302.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13201131311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600565659 + 6600565660.
It is an arithmetic number, because the mean of its divisors is an integer number (6600565660).
Almost surely, 213201131319 is an apocalyptic number.
13201131319 is a deficient number, since it is larger than the sum of its proper divisors (1).
13201131319 is an equidigital number, since it uses as much as digits as its factorization.
13201131319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 25.
The spelling of 13201131319 in words is "thirteen billion, two hundred one million, one hundred thirty-one thousand, three hundred nineteen".
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