Base | Representation |
---|---|
bin | 10011001101011100111… |
… | …000010010110111111101 |
3 | 11200012102221220221122121 |
4 | 103031130320102313331 |
5 | 133112042441033432 |
6 | 2450241315442541 |
7 | 164242431144115 |
oct | 23153470226775 |
9 | 4605387827577 |
10 | 1320113221117 |
11 | 469947552989 |
12 | 193a1b2b6451 |
13 | 97642094602 |
14 | 47c72904045 |
15 | 24514aa8197 |
hex | 1335ce12dfd |
1320113221117 has 2 divisors, whose sum is σ = 1320113221118. Its totient is φ = 1320113221116.
The previous prime is 1320113221111. The next prime is 1320113221151. The reversal of 1320113221117 is 7111223110231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1208121929316 + 111991291801 = 1099146^2 + 334651^2 .
It is a cyclic number.
It is not a de Polignac number, because 1320113221117 - 227 = 1319979003389 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1320113221091 and 1320113221100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1320113221111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660056610558 + 660056610559.
It is an arithmetic number, because the mean of its divisors is an integer number (660056610559).
Almost surely, 21320113221117 is an apocalyptic number.
It is an amenable number.
1320113221117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320113221117 is an equidigital number, since it uses as much as digits as its factorization.
1320113221117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 25.
Adding to 1320113221117 its reverse (7111223110231), we get a palindrome (8431336331348).
The spelling of 1320113221117 in words is "one trillion, three hundred twenty billion, one hundred thirteen million, two hundred twenty-one thousand, one hundred seventeen".
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