132011403334 has 4 divisors (see below), whose sum is σ = 198017105004. Its totient is φ = 66005701666.

The previous prime is 132011403323. The next prime is 132011403341. The reversal of 132011403334 is 433304110231.

132011403334 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×132011403334² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132011403299 and 132011403308.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33002850832 + ... + 33002850835.

It is an arithmetic number, because the mean of its divisors is an integer number (49504276251).

Almost surely, 2^132011403334 is an apocalyptic number.

132011403334 is a deficient number, since it is larger than the sum of its proper divisors (66005701670).

132011403334 is an equidigital number, since it uses as much as digits as its factorization.

132011403334 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66005701669.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 132011403334 its reverse (433304110231), we get a palindrome (565315513565).

The spelling of 132011403334 in words is "one hundred thirty-two billion, eleven million, four hundred three thousand, three hundred thirty-four".