Base | Representation |
---|---|
bin | 1100000000011010001000… |
… | …0111000001101001000110 |
3 | 1201202000111010201020221022 |
4 | 3000012202013001221012 |
5 | 3212241430442020314 |
6 | 44024305422151142 |
7 | 2531515623463550 |
oct | 300064207015106 |
9 | 51660433636838 |
10 | 13201154251334 |
11 | 422a63a470015 |
12 | 159257ba224b2 |
13 | 749b2c17173a |
14 | 338d215284d0 |
15 | 17d5d410b78e |
hex | c01a21c1a46 |
13201154251334 has 8 divisors (see below), whose sum is σ = 22630550145168. Its totient is φ = 5657637536280.
The previous prime is 13201154251301. The next prime is 13201154251421. The reversal of 13201154251334 is 43315245110231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 13201154251294 and 13201154251303.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 471469794677 + ... + 471469794704.
It is an arithmetic number, because the mean of its divisors is an integer number (2828818768146).
Almost surely, 213201154251334 is an apocalyptic number.
13201154251334 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
13201154251334 is a deficient number, since it is larger than the sum of its proper divisors (9429395893834).
13201154251334 is an equidigital number, since it uses as much as digits as its factorization.
13201154251334 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 942939589390.
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 13201154251334 its reverse (43315245110231), we get a palindrome (56516399361565).
The spelling of 13201154251334 in words is "thirteen trillion, two hundred one billion, one hundred fifty-four million, two hundred fifty-one thousand, three hundred thirty-four".
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