Base | Representation |
---|---|
bin | 10011001101011101010… |
… | …110110001100110110000 |
3 | 11200012110111221220010202 |
4 | 103031131112301212300 |
5 | 133112102012230222 |
6 | 2450242203014332 |
7 | 164242556103131 |
oct | 23153526614660 |
9 | 4605414856122 |
10 | 1320121211312 |
11 | 469951010052 |
12 | 193a21b0a3a8 |
13 | 97643931437 |
14 | 47c739c3c88 |
15 | 24515635892 |
hex | 1335d5b19b0 |
1320121211312 has 20 divisors (see below), whose sum is σ = 2559405524616. Its totient is φ = 659629463040.
The previous prime is 1320121211303. The next prime is 1320121211323. The reversal of 1320121211312 is 2131121210231.
It is a super-2 number, since 2×13201212113122 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26921153 + ... + 26970144.
Almost surely, 21320121211312 is an apocalyptic number.
It is an amenable number.
1320121211312 is a deficient number, since it is larger than the sum of its proper divisors (1239284313304).
1320121211312 is a wasteful number, since it uses less digits than its factorization.
1320121211312 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 53892836 (or 53892830 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 1320121211312 its reverse (2131121210231), we get a palindrome (3451242421543).
The spelling of 1320121211312 in words is "one trillion, three hundred twenty billion, one hundred twenty-one million, two hundred eleven thousand, three hundred twelve".
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