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132012123020051 is a prime number
BaseRepresentation
bin11110000001000001110111…
…101100101101101100010011
3122022102020100211110100212112
4132001001313230231230103
5114300341311443120201
61144433310533215535
736543363321163361
oct3601016754555423
9568366324410775
10132012123020051
113907703299444a
1212980a00a915ab
1358878c75c47b1
1424855c6b30631
15103de119e70bb
hex781077b2db13

132012123020051 has 2 divisors, whose sum is σ = 132012123020052. Its totient is φ = 132012123020050.

The previous prime is 132012123019969. The next prime is 132012123020087. The reversal of 132012123020051 is 150020321210231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132012123020051 - 238 = 131737245113107 is a prime.

It is a super-2 number, since 2×1320121230200512 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132012123019999 and 132012123020026.

It is not a weakly prime, because it can be changed into another prime (132012123020851) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66006061510025 + 66006061510026.

It is an arithmetic number, because the mean of its divisors is an integer number (66006061510026).

Almost surely, 2132012123020051 is an apocalyptic number.

132012123020051 is a deficient number, since it is larger than the sum of its proper divisors (1).

132012123020051 is an equidigital number, since it uses as much as digits as its factorization.

132012123020051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 132012123020051 its reverse (150020321210231), we get a palindrome (282032444230282).

The spelling of 132012123020051 in words is "one hundred thirty-two trillion, twelve billion, one hundred twenty-three million, twenty thousand, fifty-one".