Base | Representation |
---|---|
bin | 11110000001000001110111… |
… | …101100101101101100010011 |
3 | 122022102020100211110100212112 |
4 | 132001001313230231230103 |
5 | 114300341311443120201 |
6 | 1144433310533215535 |
7 | 36543363321163361 |
oct | 3601016754555423 |
9 | 568366324410775 |
10 | 132012123020051 |
11 | 3907703299444a |
12 | 12980a00a915ab |
13 | 58878c75c47b1 |
14 | 24855c6b30631 |
15 | 103de119e70bb |
hex | 781077b2db13 |
132012123020051 has 2 divisors, whose sum is σ = 132012123020052. Its totient is φ = 132012123020050.
The previous prime is 132012123019969. The next prime is 132012123020087. The reversal of 132012123020051 is 150020321210231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132012123020051 - 238 = 131737245113107 is a prime.
It is a super-2 number, since 2×1320121230200512 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132012123019999 and 132012123020026.
It is not a weakly prime, because it can be changed into another prime (132012123020851) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66006061510025 + 66006061510026.
It is an arithmetic number, because the mean of its divisors is an integer number (66006061510026).
Almost surely, 2132012123020051 is an apocalyptic number.
132012123020051 is a deficient number, since it is larger than the sum of its proper divisors (1).
132012123020051 is an equidigital number, since it uses as much as digits as its factorization.
132012123020051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 132012123020051 its reverse (150020321210231), we get a palindrome (282032444230282).
The spelling of 132012123020051 in words is "one hundred thirty-two trillion, twelve billion, one hundred twenty-three million, twenty thousand, fifty-one".
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