Base | Representation |
---|---|
bin | 11110000001000001111101… |
… | …000100011000110011011011 |
3 | 122022102020121002222111211101 |
4 | 132001001331010120303123 |
5 | 114300342003024041102 |
6 | 1144433323512212231 |
7 | 36543365464021243 |
oct | 3601017504306333 |
9 | 568366532874741 |
10 | 132012213112027 |
11 | 39077079828926 |
12 | 12980a2709a077 |
13 | 5887910179561 |
14 | 24855d4aa2b23 |
15 | 103de19890e87 |
hex | 78107d118cdb |
132012213112027 has 2 divisors, whose sum is σ = 132012213112028. Its totient is φ = 132012213112026.
The previous prime is 132012213112009. The next prime is 132012213112067. The reversal of 132012213112027 is 720211312210231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132012213112027 - 215 = 132012213079259 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132012213111986 and 132012213112004.
It is not a weakly prime, because it can be changed into another prime (132012213112067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66006106556013 + 66006106556014.
It is an arithmetic number, because the mean of its divisors is an integer number (66006106556014).
Almost surely, 2132012213112027 is an apocalyptic number.
132012213112027 is a deficient number, since it is larger than the sum of its proper divisors (1).
132012213112027 is an equidigital number, since it uses as much as digits as its factorization.
132012213112027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 28.
Adding to 132012213112027 its reverse (720211312210231), we get a palindrome (852223525322258).
The spelling of 132012213112027 in words is "one hundred thirty-two trillion, twelve billion, two hundred thirteen million, one hundred twelve thousand, twenty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •