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1320123020112 = 24321331109208699
BaseRepresentation
bin10011001101011101011…
…101101011001101010000
311200012110122100210100100
4103031131131223031100
5133112102443120422
62450242305452400
7164242610345451
oct23153535531520
94605418323310
101320123020112
11469952036026
12193a22641100
1397644115830
1447c73d35128
15245158917ac
hex1335d76b350

1320123020112 has 240 divisors, whose sum is σ = 4144748608000. Its totient is φ = 389480555520.

The previous prime is 1320123020101. The next prime is 1320123020123. The reversal of 1320123020112 is 2110203210231.

1320123020112 is a `hidden beast` number, since 1 + 320 + 1 + 230 + 2 + 0 + 112 = 666.

It is an interprime number because it is at equal distance from previous prime (1320123020101) and next prime (1320123020123).

It is a super-3 number, since 3×13201230201123 (a number of 37 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 6221139 + ... + 6429837.

Almost surely, 21320123020112 is an apocalyptic number.

1320123020112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1320123020112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2072374304000).

1320123020112 is an abundant number, since it is smaller than the sum of its proper divisors (2824625587888).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1320123020112 is a wasteful number, since it uses less digits than its factorization.

1320123020112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 208866 (or 208857 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 1320123020112 its reverse (2110203210231), we get a palindrome (3430326230343).

The spelling of 1320123020112 in words is "one trillion, three hundred twenty billion, one hundred twenty-three million, twenty thousand, one hundred twelve".