Base | Representation |
---|---|
bin | 1100000000011010011110… |
… | …0101001111000000110111 |
3 | 1201202000201112110102221202 |
4 | 3000012213211033000313 |
5 | 3212242122442302003 |
6 | 44024322502003115 |
7 | 2531521120015241 |
oct | 300064745170067 |
9 | 51660645412852 |
10 | 13201246056503 |
11 | 422a68727465a |
12 | 15925a671649b |
13 | 749b451a621b |
14 | 338d2d7c5091 |
15 | 17d5dc1e3088 |
hex | c01a794f037 |
13201246056503 has 2 divisors, whose sum is σ = 13201246056504. Its totient is φ = 13201246056502.
The previous prime is 13201246056491. The next prime is 13201246056517. The reversal of 13201246056503 is 30565064210231.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13201246056503 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13201276056503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600623028251 + 6600623028252.
It is an arithmetic number, because the mean of its divisors is an integer number (6600623028252).
Almost surely, 213201246056503 is an apocalyptic number.
13201246056503 is a deficient number, since it is larger than the sum of its proper divisors (1).
13201246056503 is an equidigital number, since it uses as much as digits as its factorization.
13201246056503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129600, while the sum is 38.
The spelling of 13201246056503 in words is "thirteen trillion, two hundred one billion, two hundred forty-six million, fifty-six thousand, five hundred three".
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