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132013113 = 3263167317
BaseRepresentation
bin1111101111001…
…01110000111001
3100012101221221120
413313211300321
5232243404423
621033255453
73162043611
oct767456071
9305357846
10132013113
1168577451
1238264589
1321471b8b
1413765a41
15b8c9ee3
hex7de5c39

132013113 has 8 divisors (see below), whose sum is σ = 176687808. Its totient is φ = 87673584.

The previous prime is 132013103. The next prime is 132013117. The reversal of 132013113 is 311310231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 132013113 - 25 = 132013081 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 132013092 and 132013101.

It is not an unprimeable number, because it can be changed into a prime (132013117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 82870 + ... + 84447.

It is an arithmetic number, because the mean of its divisors is an integer number (22085976).

Almost surely, 2132013113 is an apocalyptic number.

It is an amenable number.

132013113 is a deficient number, since it is larger than the sum of its proper divisors (44674695).

132013113 is a wasteful number, since it uses less digits than its factorization.

132013113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 167583.

The product of its (nonzero) digits is 54, while the sum is 15.

The square root of 132013113 is about 11489.6959489797. The cubic root of 132013113 is about 509.1811966904.

Adding to 132013113 its reverse (311310231), we get a palindrome (443323344).

The spelling of 132013113 in words is "one hundred thirty-two million, thirteen thousand, one hundred thirteen".

Divisors: 1 3 263 789 167317 501951 44004371 132013113