1320134033401 has 4 divisors (see below), whose sum is σ = 1377531165312. Its totient is φ = 1262736901492.

The previous prime is 1320134033371. The next prime is 1320134033411. The reversal of 1320134033401 is 1043304310231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1320134033401 - 2⁵ = 1320134033369 is a prime.

It is a super-2 number, since 2×1320134033401² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1320134033411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28698565921 + ... + 28698565966.

It is an arithmetic number, because the mean of its divisors is an integer number (344382791328).

Almost surely, 2^{1320134033401} is an apocalyptic number.

It is an amenable number.

1320134033401 is a deficient number, since it is larger than the sum of its proper divisors (57397131911).

1320134033401 is an equidigital number, since it uses as much as digits as its factorization.

1320134033401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 57397131910.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1320134033401 its reverse (1043304310231), we get a palindrome (2363438343632).

The spelling of 1320134033401 in words is "one trillion, three hundred twenty billion, one hundred thirty-four million, thirty-three thousand, four hundred one".