Base | Representation |
---|---|
bin | 111101011110010101… |
… | …0000010010100000011 |
3 | 110121202021220220212120 |
4 | 1322330222002110003 |
5 | 4130331110430021 |
6 | 140351345255323 |
7 | 12352301542254 |
oct | 1727452022403 |
9 | 417667826776 |
10 | 132014155011 |
11 | 50a94604652 |
12 | 21703334543 |
13 | c5ab266a2b |
14 | 6564baab2b |
15 | 3679ac02c6 |
hex | 1ebca82503 |
132014155011 has 4 divisors (see below), whose sum is σ = 176018873352. Its totient is φ = 88009436672.
The previous prime is 132014155001. The next prime is 132014155051. The reversal of 132014155011 is 110551410231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132014155011 - 26 = 132014154947 is a prime.
It is a super-3 number, since 3×1320141550113 (a number of 34 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (132014155001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22002359166 + ... + 22002359171.
It is an arithmetic number, because the mean of its divisors is an integer number (44004718338).
Almost surely, 2132014155011 is an apocalyptic number.
132014155011 is a deficient number, since it is larger than the sum of its proper divisors (44004718341).
132014155011 is an equidigital number, since it uses as much as digits as its factorization.
132014155011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 44004718340.
The product of its (nonzero) digits is 600, while the sum is 24.
Adding to 132014155011 its reverse (110551410231), we get a palindrome (242565565242).
The spelling of 132014155011 in words is "one hundred thirty-two billion, fourteen million, one hundred fifty-five thousand, eleven".
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