Base | Representation |
---|---|
bin | 10011001101011110101… |
… | …010101111111101000011 |
3 | 11200012112001101021202022 |
4 | 103031132222233331003 |
5 | 133112123131142033 |
6 | 2450244310512055 |
7 | 164243244156005 |
oct | 23153652577503 |
9 | 4605461337668 |
10 | 1320143224643 |
11 | 469962485a91 |
12 | 193a2936562b |
13 | 9764836b089 |
14 | 47c768b4375 |
15 | 24517533098 |
hex | 1335eaaff43 |
1320143224643 has 2 divisors, whose sum is σ = 1320143224644. Its totient is φ = 1320143224642.
The previous prime is 1320143224619. The next prime is 1320143224657. The reversal of 1320143224643 is 3464223410231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1320143224643 - 214 = 1320143208259 is a prime.
It is not a weakly prime, because it can be changed into another prime (1320143224663) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660071612321 + 660071612322.
It is an arithmetic number, because the mean of its divisors is an integer number (660071612322).
Almost surely, 21320143224643 is an apocalyptic number.
1320143224643 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320143224643 is an equidigital number, since it uses as much as digits as its factorization.
1320143224643 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 82944, while the sum is 35.
Adding to 1320143224643 its reverse (3464223410231), we get a palindrome (4784366634874).
The spelling of 1320143224643 in words is "one trillion, three hundred twenty billion, one hundred forty-three million, two hundred twenty-four thousand, six hundred forty-three".
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