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1320143224657 is a prime number
BaseRepresentation
bin10011001101011110101…
…010101111111101010001
311200012112001101021202211
4103031132222233331101
5133112123131142112
62450244310512121
7164243244156025
oct23153652577521
94605461337684
101320143224657
11469962485aa4
12193a29365641
139764836b09a
1447c768b4385
15245175330a7
hex1335eaaff51

1320143224657 has 2 divisors, whose sum is σ = 1320143224658. Its totient is φ = 1320143224656.

The previous prime is 1320143224643. The next prime is 1320143224663. The reversal of 1320143224657 is 7564223410231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1308058839616 + 12084385041 = 1143704^2 + 109929^2 .

It is a cyclic number.

It is not a de Polignac number, because 1320143224657 - 223 = 1320134836049 is a prime.

It is not a weakly prime, because it can be changed into another prime (1320143224667) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660071612328 + 660071612329.

It is an arithmetic number, because the mean of its divisors is an integer number (660071612329).

Almost surely, 21320143224657 is an apocalyptic number.

It is an amenable number.

1320143224657 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320143224657 is an equidigital number, since it uses as much as digits as its factorization.

1320143224657 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 241920, while the sum is 40.

Adding to 1320143224657 its reverse (7564223410231), we get a palindrome (8884366634888).

The spelling of 1320143224657 in words is "one trillion, three hundred twenty billion, one hundred forty-three million, two hundred twenty-four thousand, six hundred fifty-seven".