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132015013442023 = 849859115533753
BaseRepresentation
bin11110000001000100100011…
…111110110011000111100111
3122022102111211021022000102011
4132001010203332303013213
5114300413221420121043
61144434505425055051
736543525046312525
oct3601044376630747
9568374737260364
10132015013442023
1139078286511238
1212981488a87487
135887c68390a5a
1424857bc971315
15103e03064359d
hex781123fb31e7

132015013442023 has 4 divisors (see below), whose sum is σ = 132015037474368. Its totient is φ = 132014989409680.

The previous prime is 132015013441957. The next prime is 132015013442029. The reversal of 132015013442023 is 320244310510231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132015013442023 - 29 = 132015013441511 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132015013442029) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 731715 + ... + 16265467.

It is an arithmetic number, because the mean of its divisors is an integer number (33003759368592).

Almost surely, 2132015013442023 is an apocalyptic number.

132015013442023 is a deficient number, since it is larger than the sum of its proper divisors (24032345).

132015013442023 is an equidigital number, since it uses as much as digits as its factorization.

132015013442023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24032344.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 132015013442023 its reverse (320244310510231), we get a palindrome (452259323952254).

The spelling of 132015013442023 in words is "one hundred thirty-two trillion, fifteen billion, thirteen million, four hundred forty-two thousand, twenty-three".

Divisors: 1 8498591 15533753 132015013442023