132015113 has 2 divisors, whose sum is σ = 132015114. Its totient is φ = 132015112.

The previous prime is 132015077. The next prime is 132015131. The reversal of 132015113 is 311510231.

Together with next prime (132015131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 66129424 + 65885689 = 8132^2 + 8117^2 .

It is a cyclic number.

It is not a de Polignac number, because 132015113 - 2¹⁴ = 131998729 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132015091 and 132015100.

It is not a weakly prime, because it can be changed into another prime (132015133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66007556 + 66007557.

It is an arithmetic number, because the mean of its divisors is an integer number (66007557).

Almost surely, 2^132015113 is an apocalyptic number.

It is an amenable number.

132015113 is a deficient number, since it is larger than the sum of its proper divisors (1).

132015113 is an equidigital number, since it uses as much as digits as its factorization.

132015113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90, while the sum is 17.

The square root of 132015113 is about 11489.7829831551. The cubic root of 132015113 is about 509.1837680442.

Adding to 132015113 its reverse (311510231), we get a palindrome (443525344).

The spelling of 132015113 in words is "one hundred thirty-two million, fifteen thousand, one hundred thirteen".